[pass] Use find instead of tree to search for cmd_find
Hugo Osvaldo Barrera
hugo at barrera.io
Fri Sep 26 02:04:51 CEST 2014
On 2014-09-25 22:58, Serpent7776 wrote:
> Hello,
>
> Some time ago I've sent a patch that add switch -1 (number one, not letter ell)
> to command ls that lists passwords one per line using find. I attach modified
> version that also add switch -1 to search command. Unfortunately it only accept
> one term when searching, so
>
> pass search -1 foo
>
> works, but
>
> pass search -1 foo bar
>
> will search only for foo
> This could be fixed by using
>
> find -iregex
>
> and I made it to work on FreeBSD with find -E, but GNU find does not understand
> -E option
>
`find ... | grep -e` would work similar and is really portable POSIX. It's
slightly less efficient, but: How many passwords can one have?
> Anyway hope it will be useful.
>
> --
> //Serpent7776
> diff --git a/src/password-store.sh b/src/password-store.sh
> index c85cc33..a5064a3 100755
> --- a/src/password-store.sh
> +++ b/src/password-store.sh
> @@ -228,9 +228,9 @@ cmd_usage() {
> $PROGRAM init [--path=subfolder,-p subfolder] gpg-id...
> Initialize new password storage and use gpg-id for encryption.
> Selectively reencrypt existing passwords using new gpg-id.
> - $PROGRAM [ls] [subfolder]
> + $PROGRAM [ls] [-1] [subfolder]
> List passwords.
> - $PROGRAM find pass-names...
> + $PROGRAM find [-1] pass-names...
> List passwords that match pass-names.
> $PROGRAM [show] [--clip,-c] pass-name
> Show existing password and optionally put it on the clipboard.
> @@ -304,16 +304,17 @@ cmd_init() {
> }
>
> cmd_show() {
> - local opts clip=0
> - opts="$($GETOPT -o c -l clip -n "$PROGRAM" -- "$@")"
> + local opts clip=0 one_per_row=0
> + opts="$($GETOPT -o c -l clip -o 1 -n "$PROGRAM" -- "$@")"
> local err=$?
> eval set -- "$opts"
> while true; do case $1 in
> -c|--clip) clip=1; shift ;;
> + -1) one_per_row=1; shift ;;
> --) shift; break ;;
> esac done
>
> - [[ $err -ne 0 ]] && die "Usage: $PROGRAM $COMMAND [--clip,-c] [pass-name]"
> + [[ $err -ne 0 ]] && die "Usage: $PROGRAM $COMMAND [--clip,-c,-1] [pass-name]"
>
> local path="$1"
> local passfile="$PREFIX/$path.gpg"
> @@ -327,12 +328,19 @@ cmd_show() {
> clip "$pass" "$path"
> fi
> elif [[ -d $PREFIX/$path ]]; then
> - if [[ -z $path ]]; then
> - echo "Password Store"
> + if [[ $one_per_row -eq 0 ]]; then
> + if [[ -z $path ]]; then
> + echo "Password Store"
> + else
> + echo "${path%\/}"
> + fi
> + tree -C -l --noreport "$PREFIX/$path" | tail -n +2 | sed 's/\.gpg$//'
> else
> - echo "${path%\/}"
> + if [[ -z "$path" ]]; then
> + path="."
> + fi
> + ( cd $PREFIX && find $path/ -type f -iname \*.gpg | sed -e 's/\.gpg$//' -e 's/\.\///' )
> fi
> - tree -C -l --noreport "$PREFIX/$path" | tail -n +2 | sed 's/\.gpg$//'
> elif [[ -z $path ]]; then
> die "Error: password store is empty. Try \"pass init\"."
> else
> @@ -341,10 +349,24 @@ cmd_show() {
> }
>
> cmd_find() {
> - [[ -z "$@" ]] && die "Usage: $PROGRAM $COMMAND pass-names..."
> - IFS="," eval 'echo "Search Terms: $*"'
> - local terms="*$(printf '%s*|*' "$@")"
> - tree -C -l --noreport -P "${terms%|*}" --prune --matchdirs --ignore-case "$PREFIX" | tail -n +2 | sed 's/\.gpg$//'
> + local opts one_per_row=0
> + opts="$($GETOPT -o 1 -n "$PROGRAM" -- "$@")"
> + local err=$?
> + eval set -- "$opts"
> + while true; do case $1 in
> + -1) one_per_row=1; shift ;;
> + --) shift; break ;;
> + esac done
> +
> + [[ -z "$@" ]] && die "Usage: $PROGRAM $COMMAND [-1] pass-names..."
> + if [[ $one_per_row -eq 0 ]]; then
> + IFS="," eval 'echo "Search Terms: $*"'
> + local terms="*$(printf '%s*|*' "$@")"
> + tree -C -l --noreport -P "${terms%|*}" --prune --matchdirs --ignore-case "$PREFIX" | tail -n +2 | sed 's/\.gpg$//'
> + else
> + local terms=$1
> + ( cd $PREFIX && find ./ -ipath "*${terms%|}*" -type f | sed -e 's/\.gpg$//' -e 's/\.\///' )
> + fi
> }
>
> cmd_grep() {
--
Hugo Osvaldo Barrera
A: Because we read from top to bottom, left to right.
Q: Why should I start my reply below the quoted text?
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